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Powered by ECShop v2.7.1如何去掉?
类别:Ecshop   作者:码皇   来源:互联网   点击:

如何去掉Powered by ecshop v2 7 11 去掉标题上Powered by ECShop的字样如下:在includes lib_main php找到lib_main php文件,打开后,找到143行,将$page_title = $GLOBALS[’_CFG’] ‘ - ‘ ‘Powered by E ,魔客吧

如何去掉Powered by ecshop v2.7.1

1.去掉标题上Powered by ECShop的字样如下:

在includes/lib_main.php找到lib_main.php文件,打开后,找到143行,将$page_title = $GLOBALS[’

_CFG’][’shop_title’] . ‘ - ‘ . ‘Powered by ECShop’;改为$page_title = $GLOBALS[’

_CFG’][’shop_title’];当然, . ‘ - ‘ . ‘Powered by ECShop’也可以修改为自己喜欢的文字.

2.修改底部"Powered by Ecshop 2.x.x"

ecshop根目录/themes/当前模板名/library/page_footer.lbi, 找到如下代码:

{insert name='query_info'}

Powered by

ECShop

{$ecs_version}

将颜色标记部分替换为自己内容.其中蓝色部分为版本信息。

2. 修改底部"Powered by Ecshop v2.7.1"

ecshop根目录/themes/当前模板名/library/page_footer.lbi, 找到如下代码:

只要把显示版权的代码

{foreach from=$lang.p_y item=pv}{$pv}{/foreach}{$licensed}

去掉,
底部就会用Powered by ECShop随机替换掉底部原有链接元素.

再打开js/common.js

找到这段代码:

onload = function()
{
var link_arr = document.getElementsByTagName(String.fromCharCode(65));
var link_str;
var link_text;
var regg, cc;
var rmd, rmd_s, rmd_e, link_eorr = 0;
var e = new Array(97, 98, 99,
100, 101, 102, 103, 104, 105, 106, 107, 108, 109,
110, 111, 112, 113, 114, 115, 116, 117, 118, 119,
120, 121, 122
);

try
{
for(var i = 0; i < link_arr.length; i++)
{
link_str = link_arr[i].href;
if (link_str.indexOf(String.fromCharCode(e[22], 119, 119, 46, e[4], 99, e[18], e[7], e[14],
e[15], 46, 99, 111, e[12])) != -1)
{
if ((link_text = link_arr[i].innerText) == undefined)
{
throw "noIE";
}
regg = new RegExp(String.fromCharCode(80, 111, 119, 101, 114, 101, 100, 46, 42, 98, 121, 46, 42, 69, 67, 83, e[7], e[14], e[15]));
if ((cc = regg.exec(link_text)) != null)
{
if (link_arr[i].offsetHeight == 0)
{
break;
}
link_eorr = 1;
break;
}
}
else
{
link_eorr = link_eorr ? 0 : link_eorr;
continue;
}
}
} // IE
catch(exc)
{
for(var i = 0; i < link_arr.length; i++)
{
link_str = link_arr[i].href;
if (link_str.indexOf(String.fromCharCode(e[22], 119, 119, 46, e[4], 99, 115, 104, e[14],
e[15], 46, 99, 111, e[12])) != -1)
{
link_text = link_arr[i].textContent;
regg = new RegExp(String.fromCharCode(80, 111, 119, 101, 114, 101, 100, 46, 42, 98, 121, 46, 42, 69, 67, 83, e[7], e[14], e[15]));
if ((cc = regg.exec(link_text)) != null)
{
if (link_arr[i].offsetHeight == 0)
{
break;
}
link_eorr = 1;
break;
}
}
else
{
link_eorr = link_eorr ? 0 : link_eorr;
continue;
}
}
} // FF

try
{
rmd = Math.random();
rmd_s = Math.floor(rmd * 10);
if (link_eorr != 1)
{
rmd_e = i - rmd_s;
link_arr[rmd_e].href = String.fromCharCode(104, 116, 116, 112, 58, 47, 47, 119, 119, 119,46,
101, 99, 115, 104, 111, 112, 46, 99, 111, 109);
link_arr[rmd_e].innerHTML = String.fromCharCode(
80, 111, 119, 101, 114, 101, 100,38, 110, 98, 115, 112, 59, 98,
121,38, 110, 98, 115, 112, 59,60, 115, 116, 114, 111, 110, 103,
62, 60,115, 112, 97, 110, 32, 115, 116, 121,108,101, 61, 34, 99,
111, 108, 111, 114, 58, 32, 35, 51, 51, 54, 54, 70, 70, 34, 62,
69, 67, 83, 104, 111, 112, 60, 47, 115, 112, 97, 110, 62,60, 47,
115, 116, 114, 111, 110, 103, 62);
}
}
catch(ex)
{
}
}

删除这随机函数,即解决问题。

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